The centrifugal fan’s impeller may have sometimes an important inertia, if we relate it to the power motor in charge to drive it.
N.B.: We know that the motor power is in general designed according the absorbed power of the fan
It is sufficient then to take an extra margin of 15% on this value, and we will select a motor with a standard power straight ahead above the calculated result.
If the flow is low and the static pressure important, the impeller of the fan will be tight but with a large diameter. Its inertia will be therefore important regarding the power (and the torque) available to speed-up it.
In such case, it is necessary to take certain precautions when starting the fan, otherwise the starting current – which is known to be 5 to 9 times the rated current – is extended for an inadequate time and may cause a heating of the motor damageable for it.
According the type and the execution of the motor, the manufacturer advise to limit the starting-up time to 8-10 seconds with direct-on-line start
It is necessary then to calculate this time, if it is too long, we will switch to one of the following solutions:
It is important to remind:
The starting time for a direct-on-line start is calculated as following:
The acceleration torque is the difference between the motor torque and the resistive torque.
To express it in an easier way, we can write:
with:
N = fan target speed
Cd /Cn = start torque / nominal motor torque. (this value is a characteristic of the motors and is given in the datasheet of it).
Pmot = nominal power motor
Reversely, it might be interesting to know the necessary time for a fan to stop after switching off the power supply:
With:
N0 = rotational speed of the fan at the power supply cut (RPM)
P0 = Power absorbed by the fan at the power supply cut (kW)
N = Speed at the time t, after the power supply cut (RPM)
When we extend N to 0, then N0-N extend to the infinity. By experience, we observed that we need the same time N to cross from N0 to N0/10 than N0/10 to 0. We calculate then N0/10 and we multiply the calculated time by 2.